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Custom Login from main Process in Electron App

electron
auth0js
custom-login

#1

I have previously asked about this here: https://auth0.com/forum/t/electron-auth0-from-main-process-with-auth-js/5609/6

I am trying to authenticate a user and obtain their app_metadata from the main process of an electron app. Using webAuth.client.login() works fine, however, calling webAuth.client.userInfo() afterwards does not include the user’s app_metadata.

Unfortunately, webAuth.client.login() also does not include the userId, which prevents me from using the management api to fetch the user_profile instead.

Is there a simple guide on how to authenticate a user using the authentication api without any redirects or popups? I know about the pkce demos (https://github.com/darkyen/pkce-demos/) but am having trouble implementing them without forcing the user to leave the electron app and logging in inside his browser.

(EDIT: Also see https://auth0.com/forum/t/getuserprofile-equivalent-in-auth0-js-v8/4916)


#2

The webAuth.client.login() uses the the /oauth/token endpoint which is part of the features available under the scope of API Authorization and OIDC conformance. The side effect of this is that non-standard/custom claims like app_metadata are not automatically included or mapped to the issued ID token.

You have to include custom claims explicitly through the means of a rule (read more about this at OIDC - User Profile Claims).

Using a rule you can add this information to the token (take in consideration that the claim type/name has to use a namespace so there’s not possibility to conflict with future OIDC claims):

function (user, context, callback) {
  if (context.idToken) {
    context.idToken"http://example.com/meta"] = user.app_metadata;
  }

  callback(null, user, context);
}

Also note that the user_id is already included in the ID token by default; it just uses the OIDC claim type of sub, which refers to the subject claim that represents the user identifier at the associated OIDC issuer (which is the Auth0 user_id).


#3